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When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) and E\(_2\) are...

Physics
WAEC 2020

When two cells of negligible internal resistances and equal e.m.f. denoted by E\(_1\) and E\(_2\) are connected in parallel, combined e.m.f. E is given by
 

  • A. E = E\(_1\) + E\(_2\)
  • B. \(\frac{1}{E} = \frac{1}{E_1} + \frac{1}{E_2}\)
  • C. E = E\(_1\) = E\(_2\)
  • D. E = \(\frac{E_1}{E_2}\)
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Correct Answer: Option C
Explanation

 If two cells of equal emf s are connected in parallel then the effective emf is equal to the emf of any one of the cells. 


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WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 127076
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