The magnitude of the force experienced by a charge of 1.6 x 10\(^{-8}\)C in a uniform electric field of intensity 5 x 10\(^5\)NC\(^{-1}\) is
E = \(\frac{\text{F}}{\text{q}}\)
Force F = E x q
F = 5 x 10\(^5\) x 1.6 x 10\(^{-8}\) = 8.0 x 10\(^{-3}\)N
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