A 60kg man stands on a weighing balance in an elevator. If the elevator accelerates upwards at 5ms\(^{-2}\), determine the reading of the scale. [g = 10ms\(^{-2}\)]
 

Mherciiakinzzy

4 years ago

F=m(g+a)
(it is addition because the elevator is accelerating upwards)
Hence, F=60(10+5)
F=60 × 15=900N

mrdave01

3 years ago

Option D is correct
The total resultant force acting on the elevator whil;
ascending ( ma + mg)
= m ( a+g)
= 60kg ( 5mls² + 10m/s²)
= 900N
If descending = m ( a - g) then ; the acceleration of the body elevated must be greater than the gravitational acceleration" g"

damolaadeyemi19

4 years ago

Formula

R= Ma + Mg

R=M(a+g)

= 60(5+10)

R = 900N

excelosamwonyi

3 years ago

I think since the lift is moving upward the reaction R is greater than the weight mg. So taking net forces in the direction of motion:
R-mg=ma
R=mg+ma
R=m{g+a}
R=60{10+15}
R=60 x 15
R=900N
Answer is D

abdulsalam.saliu

4 years ago

Yes for an elevator to move upward it has to generate enough force to lift it own weight and (plus) that of the man. So the Net Force(F) = mg+ma.

mat1560

1 year ago

Or F=ma+ F=mg