An electron of mass 9.1 x 10\(^{-31}\) kg moves with a speed of 2.0 x 10\(^6\) ms\(^{-1}\) round the nucleus of an atom in a Circular path of radius 6.1 x 10(^{11}\) m. Determine the angular speed of the electron.
Angular speed of the electron (W)
w = \(\frac{Velocity}{Radius} = \frac{V}{R}\)
= \(\frac{2.0 \times 10^6}{6.1 \times 10^{11}}\)
= 3.28 x 10\(^{16}\) rads\(^{-1}\)
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