An electron of mass 9.1 x 10\(^{-31}\) kg moves with a speed of 2.0 x 10\(^6\) ms\(^{-1}\) round the nucleus of an atom in a Circular path of radius 6.1 x 10(^{11}\) m. Determine the angular speed of the electron.

a

3.28 x 10\(^{16}\) rad s\(^{-1}\)

b

8.55 x 10\(^{3}\) rad s\(^{-1}\)

c

9.11 x 10\(^{13}\) rad s\(^{-1}\)

d

5.22 x 10\(^{15}\) rad s\(^{-1}\)

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a

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Discussions (5)

Anonymous2009
5 months ago

how in this universe is (2 x 10^6)/(6.1 x 10^11) = 3.28 x 10^16

Akrano
4 years ago

You solved it and the answer is there but its all marked wrong in the answer part after submitting

kos2297
4 years ago

the answer is A but you marked all wrong

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