Two divers G and H are at depths 20m and 40m, respectively below the water surface in a lake. The pressure on G is p\(_1\) while the pressure on H is P\(_2\), If the atmospheric pressure is equivalent to 10m of water, then the value of P\(_2\)/P\(_1\) is?
Atmospheric pressure equivalence of 10m of water
: \(\frac{p_2+10}{p_1+10}\)
= \(\frac{40+10}{20+10\)
= \(\frac{50}{30}\) = 1.67
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