The lower and upper fixed points marked on a Mercury-in-glass thermometer are 210mm apart. The end of the mercury column in the tube is 49mm above the lower fixed point in a room. What is the temperature of the room in degrees Celsius?
\(\frac{49 - 0}{210 - 0}\) = \(\frac{\theta - 0}{100 - \theta}\)
\(\frac{49}{210} = \frac{\theta}{100}\)
49 x 100 = 210 x \(\theta\)
\(\theta = \frac{4900}{210}\) = 23.3\(^o\)
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