The lower and upper fixed points marked on a Mercury-in-glass thermometer are 210mm apart. The end of the mercury column in the tube is 49mm above the lower fixed point in a room. What is the temperature of the room in degrees Celsius?
55.3\(^o\)C
23.3\(^o\)C
49.0\(^o\)C
16.43\(^o\)C
Explanation
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This should be 49-0/210-0=theta-0/100-0
Instead of 49-0/210-0=theta-0/100-theta
Note: 100-0 not 100-theta

FIRST METHOD
Draw your thermometer to make it easier to understand;
----100*C```````----- 210mm
I``````````````I
I``````````````I
I``````````````I
I x________________I 49mm
I``````````````I
----0*C`````````----- 0mm
(X-0) over (100-0) = (49-0) over (210-0)
X over 100 = 49 over 210
cross multiply
210X = 4900
X = 23.3*C
SECOND METHOD
{\} = t over T
where; {\} is the temperature of the room
t is rise above fixed point (49mm)
T is the distance between fixed point (210)
so; {\} = 49 divided by 210
=23.3*C



