A ship travelling towards a cliff receives the echo of its whistle after 3.5 seconds. A short while later, it receives the echo after 2.5 seconds. If the speed of sound in air under the prevalling condition is 250ms -1, how much closer is the ship to the cliff?

a

10m

b

350m

c

175m

d

125m

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Explanation

Correct Option
d

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Discussions (4)

Abdulesun
4 years ago

Also👇
Given: t1 3.5sec, t2 2.5sec velocity 250m/s–¹ , d?
Note (d) is distance or depth
From t=2d/v

At 3.5sec
3.5=2d/250
d=3.5x250/2
d = 437.5m

At 2.5sec
2.5=2d/350
d=2.5x250/2
d=312.5

Therefore, 437.5–312.5=125m
===> D

Leah300
3 years ago
Image

You could solve it like this

Softbash
1 year ago

thanks

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