The effect of closing the key K in the circuit shown in the figure above would be to?
When K is open. Total Resistance = 8 + 2 = 10\(\Omega\)
1 = \(\frac{V}{\Omega}\) = \(\frac{6v}{\Omega}\) = 0.6A
Where K is closed, \(\frac{1}{8} + \frac{1}{8} = \frac{1}{\Omega}\)
\(\frac{2}{8} = \frac{1}{\Omega}\)
\(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\)
\(\Omega\) = \(\frac{8}{2}\) = 4\(\Omega\)
4\(\Omega\) in series with 2\(\Omega\)= 6\(\Omega\)
1 = \(\frac{V}{\Omega}\) = \(\frac{6}{6}\) = 1A
1 - 0.6A = 0.4A increase
There is an explanation video available below.
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