A stone of mass 20g is released from a catapult whose rubber is stretched through 5cm.  If the force constant of the rubber is 200Nm\(^{-1}\), calculate the speed with which the stone leaves the catapult.

 

Download Offline App Ask a Question

Explanation

Video Explanation

No video available

Post your Contribution

Share:

Discussions (3)

Clash123
2 years ago

why is physics damnnn hardd😭

KingDeo
2 years ago

½Ke2 = ½mv6
½ x 200 x (0.05)2 = ½ x 0.02 x v2
v2 = 25

v = 5 m s−1

Quick Questions

Ask a Question
CO

ceoofwahala

20th June, 2026

Chemistry


2 comments

ASSAAS

20th June, 2026

English Language


5 comments

infinitehoaxx

21st May, 2026

Computer


4 comments