A mass of 0.5kg is whirled in a vertical circle of radius 2m at a steady rate of 2 rev/s. Calculate the centripetal force

Mcdangenius

6 years ago

Myschool! Myschol!! Myschool!!!, how many times did i call you people?, the answer is 157.954, which is approximately 158, make correction ASAP

Brightonexcellent

1 year ago

F = (mv^2)/r
V = wr.
w = is the angular velocity
r = radius = 2 m
360° = 2π rad
Therefore, 2 rev/sec = 2 × 360 = 720°
(Let us convert it to rad)
(720 × 2 ×3.142) ÷ 360 = 12.568 rad/sec
w = 12.568rad/sec

V = wr = 12.568 × 2 = 25.136 m/sec
F= (mv^2)/r
F = (0.5×25.136^2)÷2
F= 157.954. Newton
F = 158 N (approx.)

Answer is C

mmesomaxx

2 years ago

Y did you guys cancel radius r whereas from the question radius is 2