The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.
M\(_r\)(90 - 50) = 0.2(100 - 90)
40M\(_r\) = 0.2 × 10
| M\(_r\) | = | 2
40 |
= | 0.05kg |
There is an explanation video available below.
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}