Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss.
Specific heat capacity of copper = 400JKg-1K-1
Latent heat of fusion of ice = 3.3 x 10\(^5\)JKg-1
a
8/33kg
b
33/80kg
c
80/33kg
d
33/8kg
Explanation
Correct Option
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Discussions (14)
Dseasoner
13 years ago
Since the boilin point of water is 100°C the temp. of the copper will be 100°C and since no heat is lost from the transfer,
mcΔΘ=m(ice) x l
where
m=mass of copper=2kg
m(ice)=mass of ice
c=Specific heat capacity of copper=400
ΔΘ=change in temperature=(100-0)=100
l=latent heat of fussion of ice=3.3x10^5
2x400x100=m(ice)x3.3x10^5
m(ice)=80000/330000
m(ice)=8/3
Olorodeimisi
5 years ago
The temp. should have been converted to kelvin, since the specific heat capacity is in term of kelvin
