A copper rod, 5m long, when heated through 10ºC, expands by 1mm. If a second copper rod, 2.5m long, is heated through 5ºC, by how much will it expand?
4mm
0.25mm
2mm
0.12mm
Explanation
Video Explanation
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Discussions (21)
guys it's
5 m----> 1mm
2.5m--->xmm
make x the subject formula
5x=2.5
x=2.5/5
x= 0.5 mm
T1= 10°c
T2= 5°c
T1/T2
10/5=2°c
0.5mm÷ 2
1/2÷ 2/1
1/2× 1/2
= 1/4
which is 0.25
instead of solving long calculation in the hall, kind use the logical method I'm going to share with u guys
since the second length is half of the initial length that is 1/2, and the second temperature is half of the initial temperature that is 50.
then half of length will multiply by half of temperature.
tha is
1/2 x 1/2
= 1/4
= 0.25mm.
I hope this can be helpful
this explanation needs modification ok.
1/8= 0.125 not 0.25 mm
also it's 10°c not 20°c which the guy solved with
