The volume of 0.354g of helium at 273°C and 114cmhg of mercury pressure is 2667cm\(^3\). Calculate the volume at STP.
m = 0.354g, T\(_1\) = 273°C = 273 + 273 = 546K
P\(_1\) = 114cmHg, V\(_1\) = 2667cm\(^3\) at STP
T\(^2\) = 273K, P\(_2\) = 76cmHg, V\(_2\) = ?
\(\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_1}\)
= 2000.25cm\(^3\)
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