(a) Explain what is meant by: (i) electric field intensity ; (ii) electric lines of force.
(b) Two similar but opposite point charges -q and +q each of magnitude \(5 \times 10^{-8} C\) are seperated by a distance of 8.0cm in vacuum as shown in the diagram below.

Calculate the magnitude and direction of the resultant electric field intensity E at the point P. Draw the lines of force due to this system of charges. [Take \(\frac{1}{4 \pi \varepsilon _{0}}\)]
(c)
Calculate the following in the series circuit shown above: (i) reactance of the capacitor ; (ii) impedance of the circuit ; (iii) current through the circuit ; (iv) voltage across the capacitor ; (v) average power used in the circuit.
Explanation
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Discussions (1)

I think there is mistake in (v) average power used in the circuit but, correct me if i am wrong.
the formula for average power is πππ£ = πΌπ cos Ξ¦ not P=IV
πππ£ = πΌπ cos Ξ¦
Ξ¦π
πΆ = tanβ1 (ππΆ/π
)
= tanβ1 (636.62/1000)
= 32.48Β°
πππ£ = 0.0759 Γ 90 Γ cos(32.48)
=6.831 Γ 0.8436
=5.763W
β5.8W

