(a) Explain what is meant by: (i) electric field intensity ; (ii) electric lines of force.

(b) Two similar but opposite point charges -q and +q each of magnitude \(5 \times 10^{-8} C\) are seperated by a distance of 8.0cm in vacuum as shown in the diagram below.

Calculate the magnitude and direction of the resultant electric field intensity E at the point P. Draw the lines of force due to this system of charges. [Take \(\frac{1}{4 \pi \varepsilon _{0}}\)]

(c)  

Calculate the following in the series circuit shown above: (i) reactance of the capacitor ; (ii) impedance of the circuit ; (iii)  current through the circuit ; (iv) voltage across the capacitor ; (v) average power used in the circuit.

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Timboyyy
7 months ago

I think there is mistake in (v) average power used in the circuit but, correct me if i am wrong.
the formula for average power is π‘ƒπ‘Žπ‘£ = 𝐼𝑉 cos Ξ¦ not P=IV
π‘ƒπ‘Žπ‘£ = 𝐼𝑉 cos Ξ¦
Φ𝑅𝐢 = tanβˆ’1 (𝑋𝐢/𝑅)
= tanβˆ’1 (636.62/1000)
= 32.48Β°

π‘ƒπ‘Žπ‘£ = 0.0759 Γ— 90 Γ— cos(32.48)
=6.831 Γ— 0.8436
=5.763W
≃5.8W

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