2007 WAEC Physics Theory  A particle is projected at an angle of 30° to the horizontal with a speed...

A particle is projected at an angle of 30° to the horizontal with a speed of 250 ms\(^{-1}\). Calculate the;

(a) total time of flight of the particle;

(b) speed of the particle at its maximum height. [ g = 10 ms\(^{-2}\)]

(a) T = \(\frac{2Usin\theta}{g} = \frac{2 \times 250 \times sin 30}{10}\)

= 25s

(b) Speed at h\(_{\text{max}} Ucos \theta\)

= 250 cos 30\(^o\) = 216m/s

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