A particle is projected horizontally at 15ms\(^{-1}\) from a height of 20m.
Calculate the horizontal distance covered by the particle just before hitting the ground.
[g = 10 ms\(^{-2}\)]
The expected answer is:
Let R represent the horizontal distance covered at time, t.
h = ½ gt\(^2\)
20 = ½ x 10 x t\(^2\)
t = 2 s
R = ut
= 15 x 2
= 30m
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}