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2015 WAEC Physics Theory  (a) Define nucleon number (b) A radioactive isotope of Americium (Am —241) decays into a...

Physics
WAEC 2015

 (a) Define nucleon number

(b) A radioactive isotope of Americium (Am —241) decays into a nucleus of Neptunium (Np — 237) and an alpha (\(\alpha\)) particle as shown in the nuclear equation below. \(^{241}_{95}Am\) \(\to\) \(^{237}_{c} + ^b_a \alpha\)

(i) State the number of neutrons in the nucleus of Americium — 241.

(ii) Determine the values of a,b and c.

(c)(i) Why are y-rays not deflected by electromagnetic field?

(ii) State two properties of gamma rays that make them suitable for sterilizing medical equipment.

(d) A sample of radioactive substance was found to be left with h of its initial count rate after 110 years. Calculate its decay constant.

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Explanation

(a) Nucleon number is the total number of protons and neutrons in the nucleus of an atom.

 

(b)(i) Number of neutrons in the nucleus of Americium = 241 - 90 =146.

(ii) a = 2

b = 4

c = 95 - 2

= 93.

 

(c)(i) Y-ray are electrically neutral or carry no charge.

(ii) properties of gamma rays that makes them suitable for medical sterilization of equipment are:

(1) Possession of strong penetrating power.

(2) Posession of low ionizing power.
 

(d) \(\frac{N}{N_o} = (\frac{1}{2})^a = \frac{1}{32} = (\frac{1}{2})^a\) = (\(\frac{1}{2})^5\)

But T\(_\frac{1}{2}\) = \(\frac{t}{n} = \frac{110}{5}\) = 22 years

Hence \(\lambda\) = \(\frac{0.693}{T_{\frac{1}{2}}} = \frac{0,693}{22}\)

Decay constant \(\lambda\) 3.2 x 10\(^{-2}\) per year

 


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