A body is projected at an angle of 30° to the horizontal with a velocity of 150 ms\(^{-1.}\). Calculate the time it takes to reach the greatest height [Take g = 10 ms\(^2\) and neglect air resistance]
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emma_diamond
4 years ago
u=150ms‐¹
¤=30°
g=10ms‐¹
t=time taken to reach maximum height = ?
t=usin¤÷g
t=150×sin30÷10
t= 7.5secs.
Isr123
3 years ago
timetaken to get to maximum hight and not time of flight which is twice timetaken:
t=usinO^/g
where;
t=?
u=150m/s
O^=30
g=10
t=150sin30/10
t=150*0.5/10
t=7.5s
if time of flight,T=2t
T=2*7.5
T=15s
Who is with me?
Debbypebby
4 years ago
Using
T=2Usin©/g
g= acceleration due to gravity given as 10m/s²
T=2*150 sin 30/10
Where sin 30= 0.5
T=2*150*0.5/10
T=15secs.
