n = \(\alpha\)	0.06eV
E=3	-1.6eV
E=2	-3.7eV
E=1	-5.5eV
E=0	-10.4eV

The energy levels in the mercury atom is illustrated in the table above. Calculate the ionisation energy of the atom.

Godwinchikamso

3 years ago

E=E2-E1
E=0.0eV-(-10.4)eV
E=0.0eV+10.4eV
E=10.4eV

Hhs

1 year ago

Ionization is the transition from the
ground state 𝐸o (where n=1) to the highest energy level 𝐸∞ (n=∞)
Hence Ionization energy is given by,
𝑬i= ∆𝑬 = 𝑬∞ − 𝑬o
∆E = 0.00-(-10.4). { note that it's not 0.06 as }
= +10.4. { in the question, because }
{ n∞ is always equal to 0. }

Simply note that, Ionization energy is the
positive value of the ground state energy.