A motorist travelling at 72\(kmh^{-1}\) had his eyes shut for 0.4s during a hard sneeze. Calculate the distance covered by him during this time interval.
Convert velocity from \(kmh^{-1}\) to \(ms^{-1}\), by multiplying \(\frac{1000}{3600}\),
\(72 \times \frac{1000}{3600}\) = \(20ms^{-1}\)
Therefore, distance covered in 0.4s = \(20 \times 0.4 = 8m\)
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