Two objects P and Q of masses 100kg and 20kg respectively are 1.2m apart on a horizontal surface. Calculate the net gravitational force acting on Q. \([G= 6.67 \times 10^{-11} Nm^{2}kg^{-2}]\)
\(1.11\times 10^{-7} N\) towards P
\(1.11\times 10^{-7} N\) towards Q
\(9.26\times 10^{-8} N\) towards P
\(9.26\times 10^{-8} N\) towards Q
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Discussions (9)
Shouldn't the net force on Q actt towards P since P is the heavier object?
The correct answer is C. Gravitational force is always that of attraction (no repulsion). Hence both masses experience a pull on each other. The pull on Q is towards P.
The direction of the net gravitational force is determined by the relative masses of the objects involved. In this case, the force is acting on object Q due to the gravitational pull from object P.
Given that object P has a much larger mass (100 kg compared to 20 kg for object Q), the net gravitational force will act towards P.
So, the correct answer is:
C. 9.26 X 10^-8N towards P
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The gravitational force acts towards P becsuse gravitational force is always attractive.
Final Answer:
C.
