A bar AB is balanced horizontally on two knife edges as illustrated as in the diagram above. Determine the weight of the bar.

Chrisbridge

6 years ago

The sum of the upward forces = sum of downward force(weight of the bar)

Kayma

3 years ago

the forces are moving in opposite direction;
F1+F2=20N+20N
=40N

Fasola4peace

2 years ago

The weight of the bar is acting downward. This is the only force that counterbalances the efeect of two upward forces (i.e 20N on the two pivot). For the bar to balance horizontally (at equibrium), the total upward forces must equal to the total downward forces. Therefore, the weight of the bar = 20N + 20N = 40N

Anjy.xx

1 year ago

J

Benny374

2 years ago

I'm confused here

Amatie

4 years ago

The correct answer is E. ie
Clockwise moment = Anti clockwise moment
weight(downward force)at A x 20 = 50 x20
Weight(downward force) at A = 1000/20
Weight(downward force) kat A = 50N