A 20kg mass is to be pulled up a slope inclined at 30° to the horizontal. If efficiency of the plane is 75%. The force required to pull the load up the plane is J [g=10ms\(^{− 2}\)]

JThomson

7 years ago

V.R=1/Sinθ

V.R=2

M.A=0.75×2

=1.5

M.A=Load/Force

Force=Load/M.A

=(20×10)/1.5

=133.3 N

dominiontech

7 years ago

The answer is C

Newton2i

2 years ago

efficiency = work output / work input
work output = 20 x 10 = 200N
eff = 75/100 = 0.75
0.75 = 20 x 10 / 2 w
0.75 x 2w = 200
1.5w = 200
w = 200/1.5 = 133.3 N

sabieik

6 years ago

The answer and explanation is wrong