The density of 400cm\(^3\) of palm oil was 0.9gcm-3 before frying. If the density of the oil was 0.6gcm-3 after frying, assuming no loss of oil due to spilling, its new volume was?

Vickyvic

7 years ago

V1 * D1= V2 * D2
400*0.9=0.6* V2
V2=360/0.6
V2= 600cm2

Neekgee

7 years ago

0.9+0.6=1.5
1.5*400=600

Award0001

2 years ago

D = m/v
m = Dv
D1v1 = D2v2
D1 = 0.9g/cm³
v1 = 400cm³
D2 = 0.6cm³
v2 = ?
v2 = D1v1/D2
v2 = 0.9*400/0.6 = 600cm³

Sensei

2 months ago

correct 👍💯