A man walks 1km due east and then 1 km due north His displacement?

dtlcrepublic

7 years ago

First lets calculate the distance

1km North
1km Easth

thus, we'll get 1km + 1km giving us 2km.

Now a circumference is 360⁰, and the distance (displacement) cover half a circumference. which leaves us with half of a circumference, which is 90⁰.

now, 2√90⁰; gives us 45⁰.

which means that the displacement was 45⁰ North and 45⁰ East.

so the answer is √2km 45⁰.

Anjola_taiwo

7 years ago

Using pythagoras theorem R²=1²+1² =√2
TO GET THE DIRECTION TAN=OPP/ADJACENT
TAN = 1/1 = 45°

ugijo

6 years ago

Moving

_______________1m East
I
I
I
I
1m. North

Would form

A right angke triangle
___
I /
I /

With an angle of 90ⁿ North East

The resultant would then be the hypotenus

Which magnitude would be calculated as 1²+1² =R² (from Pythagoras theorem)
R²=1+1
R²=2
R=√2

The direction =
The resultant would be the hypothenus (a strait line drawn to join tye two point)

Which devides the right angle triangle of 90ⁿ into two (90/2) =45ⁿ


Therefore diplacement = √2kmN45ⁿE
(A)

ItodoQueen

4 years ago

No explanation