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A man walks 1km due east and then 1 km due north His displacement?

Physics
JAMB 2018

A man walks 1km due east and then 1 km due north His displacement?

  • A. √2km N 45°E
  • B. 1km N 30°E
  • C. 1km N 15°E
  • D. √2km N 60°E
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Correct Answer: Option A
Explanation

His movements 1km due east and then 1 km due north make a Right-Angled Triangle.

Using Pythagoras' theorem;

The Resultant becomes the Hypotenuse [h]

Hyp\(^2\) = Adj\(^2\) + \Opp(^2\)

Hyp\(^2\) = 1\(^2\) + 1\(^2\)

Hyp\(^2\) = 2 → Hyp = √2

: Resultant = √2

DIRECTION TAN Ø = \(\frac{OPP}{ADJ}\) 

TAN Ø = \(\frac{1}{1}\)

Ø = TAN\(^{-1}\) [1]

Ø= 45°

Displacement is √2km N 45°E

There is an explanation video available below.


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Explanation Video

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