Correct Answer: Option B

Explanation

V = IR from ohms law

I = \(\frac{V}{R}\)

Since the resistances are in parallel

\(\frac{1}{Reff}\) = \(\frac{1}{18}\) + \(\frac{1}{12}\) + \(\frac{1}{6}\)

= \(\frac{2 + 3 + 6}{36}\) = \(\frac{11}{36}\)

R\(_{eff}\) = \(\frac{36}{11}\) = 3.27

I = I\(_1\) + I\(_2\) + I\(_3\)

= \(\frac{V}{Reff}\)= \(\frac{12}{3.27}\)

= 3.669A

I = 3.7A

There is an explanation video available below.

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