Physics
JAMB 2017
From the diagram above, calculate the energy stored in the capacitor
-
A.
4.0 x 10\(^{-2}\)J
-
B.
4.0 x 10\(^{-4}\)J
-
C.
8.0 x 10\(^{-4}\)J
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D.
8.0 x 10\(^{-2}\)J
Correct Answer: Option B
Explanation
c = 8µF, v = 10v
Energy stored = \(\frac{1}{2}\) cv
2
= \(\frac{1}{2}\) × (8 × 10− 6) × 10
2
= 4 × 10\(^{-4}\)
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