Correct Answer: Option B

Explanation

The relationship between the peak value and r.m.s value of electricity supply is given as

V\(_{r.m.s}\) = \(\frac{V_o}{\sqrt{2}}\)

where V_o = peak voltage

∴ V_o = V\(_{r.m.s}\) × √2

= 240 × √2

= 339.5v

= 340v

There is an explanation video available below.

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