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Calculate the specific latent heat of vaporization of steam of 1.13 x 106J of heat...

Physics
JAMB 2017

Calculate the specific latent heat of vaporization of steam of 1.13 x 106J of heat energy is required to convert 15kg of steam to water.

  • A. 7.53 x 105 Jkg\(^{-1}\)
  • B. 7.53 x 10-2Jkg\(^{-1}\)
  • C. \(7.53 \times 10^{4}\)Jkg\(^{-1}\)
  • D. 7.53 x 10-3Jkg\(^{-1}\)
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Correct Answer: Option C
Explanation

Quantity of heat = mass(m) × specific latent heat (L)
Q = mL
L = \(\frac{Q}{m}\)

= \(\frac{1.13 \times 10^{6}}{15}\)

= \(7.53 \times 10^{4}\)Jkg\(^{-1}\)

There is an explanation video available below.


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Explanation Video

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