Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density \(10^{3}\) kgm-3 [g = 10ms-2]

a

0.8N

b

2.5N

c

0.5N

d

1.0N

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Explanation

Correct Option
c

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Discussions (18)

Ruqqayyah1
8 years ago

Density=mass÷volume
Mass of the liquid =density ×volume ×acceleration due to gravity
Density 103kgm convert to gm =103÷1000=0.103gm while volume 50cm=50÷100=0.5m
Therefore, 0.5×0.103×10=0.5

benningsen
3 months ago

Answer is right but steps are quite mystifying. it's just simple like this,

Upthrust/Buoyancy= PVG(density, volume,gravity)
remember converting cm³ to m³ is cm³/1,000,000 making 50cm³ to be 0.00005
and 10³ is same as 1000
therefore, 1000x0.00005x10=0.5.
it's that simple ✍️✍️

Ruqqayyah1
8 years ago

That's calculation is nonsensical

Rx.Nino
2 years ago

You can simply use the formula: Upthrust=PVG (P= Density, V= Volume, G= Acceleration due to gravity)
Converting 50cm³ to m³ - 50×10^-6m³
Upthrust = 10³×5×10^-5×10
Upthrust= 0.5N

Nemozoldyck
1 year ago

omo, this formula is one kind 😂
the one i use is upthrust= volume×density×acceleration due to gravity

adeboy1866
8 years ago

The answers is 2.5

Fayeeofficial
1 year ago

i don't understand

ajibadeo
8 years ago

103x(50x10^-6) will give 5.15x10^-3 that means the answer will be wrong

Kay111
8 years ago

the density is wrong if the answer is truly right.
it should be 100kg/m³ instead.

miracletom1999
8 years ago

very nonsensical....

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