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Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of...

Physics
JAMB 2017

Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density \(10^{3}\) kgm-3 [g = 10ms-2]

  • A. 0.8N
  • B. 2.5N
  • C. 0.5N
  • D. 1.0N
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Correct Answer: Option C
Explanation

Upthrust = change in weight

density = \(\frac{\text{mass}}{\text{volume}}\)

Mass of liquid displaced = Density of Liquid × Volume;

= \(10^{3} \times 50 \times 10^{−6}m^{3}\)

= 0.05kg

(Note that the volume of \(50cm^{3}\) was converted to \(m^{3}\) by multiplying by \(10^{6}\)) i.e \(50cm^{3} = 50 \times 10^{−6}m^{3}\)

Since mass displaced = 0.05kg

Upthrust = mg = 0.05 × 10

= 0.5N

There is an explanation video available below.


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Explanation Video

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WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709
Post-UTME Past Questions - Original materials are available here - Download PDF for your school of choice + 1 year SMS alerts
WAEC offline past questions - with all answers and explanations in one app - Download for free
WAEC May/June 2024 - Practice for Objective & Theory - From 1988 till date, download app now - 99995
WAEC Past Questions, Objective & Theory, Study 100% offline, Download app now - 24709