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Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of...

Physics
JAMB 2017

Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density \(10^{3}\) kgm-3 [g = 10ms-2]

  • A. 0.8N
  • B. 2.5N
  • C. 0.5N
  • D. 1.0N
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Correct Answer: Option C
Explanation

Upthrust = change in weight

density = \(\frac{\text{mass}}{\text{volume}}\)

Mass of liquid displaced = Density of Liquid × Volume;

= \(10^{3} \times 50 \times 10^{−6}m^{3}\)

= 0.05kg

(Note that the volume of \(50cm^{3}\) was converted to \(m^{3}\) by multiplying by \(10^{6}\)) i.e \(50cm^{3} = 50 \times 10^{−6}m^{3}\)

Since mass displaced = 0.05kg

Upthrust = mg = 0.05 × 10

= 0.5N

There is an explanation video available below.


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Explanation Video

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