Physics jamb 2017

Calculate the electric field intensity between two plates of potential difference 6.5V when separated by a distance of 35cm.

a

18.57NC\(^{-1}\)

b

53.06N C\(^{-1}\)

c

2.28NC\(^{-1}\)

d

0.80NC\(^{-1}\)

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Explanation

Correct Option
a

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Discussions (12)

Lecxygold
7 years ago

correct formula correct answer

Finesse11
3 months ago

omoh tonight's test go far

Finesse11
3 months ago

as in I just dey jam old age questions

Finesse11
3 months ago

but then the solving is spot on

ayomidehy29
8 years ago

A

Neekgee
7 years ago

I Did'nt get d solving oo

madeeeeeehah
8 years ago

the formula is wrong electric field(e)= f/q

ololajulo
7 years ago

cross check

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