Correct Answer: Option A

Explanation

Electric Field Intensity (E) = \(\frac{v}{d}\)

= \(\frac{\text{potential difference}}{\text{distance}}\)

= \(\frac{6.5v}{35cm}\)

= \(\frac{6.5}{35 \times 10^{- 2}}\)

= 18.57NC\(^{-1}\)

There is an explanation video available below.

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