Physics
WAEC 2016
The distance between two successive trough of a wave is 0.4m. If the frequency of the source is 825Hz, Calculate the speed of the wave
-
A.
165.0 ms-1
-
B.
330.0ms-1
-
C.
41.5ms-1
-
D.
85.0ms-1
Correct Answer: Option B
Explanation
v = f\(\lambda\)
= 825 x 0.4
= 330.0ms-1
Report an Error
Ask A Question
Download App
Quick Questions
Contributions ({{ comment_count }})
Please wait...
Modal title
Report
Block User
{{ feedback_modal_data.title }}