An object of volume 400cm³ and 2.5gcm^-3 is suspended from a spring balance with half its volume immersed in water. Determine the reading on the spring balance. (Density of water = 1gcm^-3)

sparrow7

9 years ago

Reading in scale = weight of the body-upthrust on the body when immersed in a fluid.



d=m/v



2.5=m/400



m=2.5x400=1000g



weight=mg =1000x10=10,000N



upthrust on the body is only acting on half the volume of the body



d=1(density of water )

g=10

v=200



upthrust, U=dgv



=1x10x200



=2000N.



reading in scale =10000-2000



=8000N.( This is the actual reading because spring balance measures weight and not mass)



but options are in grams



so W=mg



8000=mx10



m=800g..

mochad

2 years ago

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