in a nuclear fission process, the mass defect was 1.2 x 10-5kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 108ms-1]

a

1.08 x 1011J

b

5.20 x 1011J

c

1.08 x 1012J

d

2.50 x 1013J

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Abudaddy
9 years ago

E=mc^2. which is 1.2*10^-5*3.0*10^8= 1.08*10^11

Abudaddy
9 years ago

I'm sorry it should be 3.0*3.0 which square

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