Which of the following units is the S.I. unit of heat capacity?

Giuseppe.Jose

9 years ago

Here is an explanation:

Quantity of heat lost is gained is Q=mc0 (Let 0 be tetha)

making c(i.e specific heat capacity) the subject of fomula, we'll get Q/m0

ie .. c= Q/m0

taking the units for each:

Q- quantity of heat is measured in joules

m- is measured in kilogram

0- thetha is measured in kelvin.

that means joules/ kilogram X kelvin

that means J/Kg X k

our c is J/Kg X k

ie, c=J/Kgk

applying indices rule

our c becomes JKg^-1k^-1



but we were asked to find Heat capacity and not specific heat capacity . And heat capacity, big C is mc (ie C = mc)

remember that c is JKg^-1k^-1 and m is Kg

so, C= JKg^-1k^-1 X kg

using indices rule

our C is J Kg-1+1 k-1

C = J Kg^0 k^-1

C = JK^-1





HOPE THIS HELPS ;)

chizee7703

6 years ago

The right answer is C