In a school compound a girl walks 40m due east from the laboratory to the staff room to submit her report. Then she returns and walks 30m due north to her classroom. Determine the magnitude of her displacement from the10m laboratory
East (\(x\)): 40 m, North (\(y\)): 30 m
displacement: \(\sqrt{40^{2}+30^{2}}\)
= \(\sqrt{1600 + 900} = \sqrt{2500} = 50\)m.
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