A body is projected with an initial velocity U at an angle O to the horizontal. The time taken by it to reach its maximum height is given by the expression
a
\(\frac{2u \text{sin}\theta}{g}\)
b
\(\frac{u^2 \text{sin}^2\theta}{2g}\)
c
\(\frac{u \text{sin}\theta}{g}\)
d
\(\frac{u \text{sin}\theta}{2g}\)
Explanation
Correct Option
cNo explanation available
Video Explanation
No video available
Post your Contribution
Share:
