A body is projected with an initial velocity U at an angle O to the horizontal. The time taken by it to reach its maximum height is given by the expression
A.
\(\frac{2u \text{sin}\theta}{g}\)
B.
\(\frac{u^2 \text{sin}^2\theta}{2g}\)
C.
\(\frac{u \text{sin}\theta}{g}\)
D.
\(\frac{u \text{sin}\theta}{2g}\)
Correct Answer: Option C
Explanation
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