Physics
JAMB 2016
Calculate the temperature of 6 moles of an ideal gas at a pressure of 7.6 x 10
6Nm
-2 with a volume of 10
-3m
3.
[R = 8.3jmol
-1K
-1]
-
A.
201oC
-
B.
126oC
-
C.
153oC
-
D.
185oC
Correct Answer: Option C
Explanation
T = \(\frac{PV}{nR}\) = \(\frac{7.6 x 10^6 x 10^-3}{6 x 8.3}\)
= 153
oC
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