Calculate the temperature of 6 moles of an ideal gas at a pressure of 7.6 x 10⁶Nm^-2 with a volume of 10^-3m³.
[R = 8.3jmol^-1K^-1]

Yourfaveboi

1 year ago

The answer isn't even there because what you calculated/ the answer you choosed is in Kelvin

Yourfaveboi

1 year ago

1. Ideal Gas Law:
The ideal gas law is PV = nRT, where:
* P = pressure (7.6 x 10^6 Nm^-2)
* V = volume (10^-3 m^3)
* n = number of moles (6)
* R = ideal gas constant (8.3 J mol^-1 K^-1)
* T = temperature (what we want to find)
2. Rearrange the equation to solve for T:
T = PV / nR
3. Plug in the values:
T = (7.6 x 10^6 Nm^-2 * 10^-3 m^3) / (6 * 8.3 J mol^-1 K^-1)
4. Calculate:
T ≈ 153 K
5. Convert to Celsius:
T_Celsius = T - 273
T_Celsius ≈ -120°C

Korede2002

6 years ago

The formula up There is gotten from the ideal gas formula-PV=nRT

jedroy

2 months ago

it's actually supposed to be kelvin though