A radioactive isotope has a decay constant of 10\(^{-6}\)s\(^{-1}\). Calculate its half-life.
5.93 x 106s
6.93 x 105s
6.93 x 109s
5.93 x 107s
Explanation
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no the question is absolutely correct look
The half-life (t1/2t1/2) of a radioactive isotope can be calculated using the decay constant (λλ) with the formula:
t1/2=ln(2)λ
t1/2=λln(2)
Given:
Decay constant (λλ) = 10−6 s−110−6s−1
Substituting the values into the formula:
t1/2=ln(2)10−6
t1/2=10−6ln(2)
Calculating ln(2)ln(2) (approximately 0.693):
t1/2=0.69310−6≈6.93×105 s
t1/2=10−60.693≈6.93×105s
Thus, the half-life of the radioactive isotope is approximately:
B. 6.93×105 s6.93×105s.
the question is:
A radioactive isotope has a decay constant of 10 ^-6.
Calculate its half - life?
0.693/ (10^-6) = 6.93 × 10^5
k=0.693/t½
t½=0.693/k.where k is constant
sotherefore t½=0.693/10–6=6.93*10⅞
