A metre rule is pivoted at its mid-point with a vertical force of 10N hanging from the distance 30cm from the mid-point. At what distance must a 15N force hang to balance the ruler horizontally?

Elbrain

9 years ago

My First method is erroneous so use this method:

Clockwise moment = Anti-clockwise moment

10 x 30 = 15 x X

300 = 15x

x = 300/15

x = 20

Mr_Philsual

3 years ago

F1 × S1 = F2 × S2
10 × 30 = 15 × S2
300=15S2
Divide both sides by the coefficient of S2
300/15 = 15S2/15
S2= 20cm. [C]

Mosespajam

9 years ago

simple and short

angelic favour

9 years ago

thanks i can solve it now

pator

9 years ago

clock wise movement=anti clobk wise movement

10x30=300

300/15=20

Elbrain

9 years ago

Clockwise moment = Anti-clockwise moment

10 x 30 = 15 x X

30 = 15x

x = 300/15

x = 20