Calculate the work done in charging a capacitor of capacitance 20µF through a potential difference of 1000V.
a
0.02 J
b
0.10 J
c
0.20 J
d
1.00 J
e
10.00 J
Explanation
Correct Option
eNo explanation available
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Discussions (2)
SaniMBBSuniAbuja
2 years ago
The work done in chaging a capacitor is the same as the energy of a capacitor hence,
E=1/2CV²
=0.5x20x0.000001×1000x1000
=10J
Hence,Option E is valid
